how i state the minimum and maximum y- values for y=-6+4sin(x-pi)?

3 Answers

  • 4 weeks ago

    The value of sine function is always between -1 and 1 inclusive (it doesn't matter that the input is shifted).

    Then you are multiplying that by 4, so the range is now -4 to 4.

    But you are adding that to -6, so the range is -10 to -2.


    Minimum = -10

    Maximum = -2

    Check the graph in the link below.

  • You can use calculus and take the derivative then set it equal to 0, and plug that solution into the original function to get coordinates of the maxima/minima.

    Or you can look at the function and imagine the transitions of the base function y=sin(x) to determine the maxima and minima

  • sin(t) is always going to be between -1 and 1, with the ends inclusive.

    -6 + 4 * (+/- 1)

    -6 +/- 4

    -10 , -2

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