Need derivative help?

find the derivative of z(x)=sin(cos(tan(3x)))

I'm just really confused, please try and be a detailed at possible so I can better understand.

1 Answer

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  • Best Answer

    I showed you the derivative. This is just a chain rule problem

    f(t) = sin(t)

    f'(t) = cos(t) * d/dt

    g(t) = cos(t)

    g'(t) = -sin(t) * d/dt

    h(t) = tan(t)

    h'(t) = sec(t)^2 * d/dt

    j(t) = 3t

    j'(t) = 3 * d/dt

    k(t) = f(g(h(j(t))))

    k'(t) = f'(g(h(j(t)))) * g'(h(j(t))) * h'(j(t)) * j'(t)

    z'(x) = cos(cos(tan(3x))) * (-sin(tan(3x))) * sec(3x)^2 * 3 * 1

    • ted s
      Lv 7
      1 month agoReport

      the " d / dt 's " don't belong....df / dx = [ df /dg][dg/dh][dh/dj][dj/dt] by the 'chain rule'....and df/dg = cos g , ...

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