Anonymous
Anonymous asked in Science & MathematicsAlternativeOther - Alternative · 1 month ago

Can you help me to solve this math problem, please?

Two cars A and B go along two perpendicular roads with constant speeds towards the intersection (A on one road, B on the other). When A reached the intersection, the distance between the cars was 500 meters. When after that B at time T reached the intersection, the distance between the cars became 600 meters. What will be the distance between the cars when Machine A travels another 600 meters after time T?

3 Answers

Relevance
  • Best Answer

    Every time A travels 600 meters, B travels 500 meters

    When A is at (0 , 0) , B is at (-500 , 0)

    When A is at (0 , 600) , B is at (0 , 0)

    When A is at (0 , 1200) , B is at (500 , 0)

    Does that make sense to you? Can you see why A is at the point of 1200 meters away from the intersection?

    d^2 = 500^2 + 1200^2

    d^2 = 100^2 * (5^2 + 12^2)

    d^2 = 100^2 * (25 + 144)

    d^2 = 169 * 100^2

    d = 13 * 100

    d = 1300

    They're 1300 meters away from each other.

  • 1 month ago

    A reaches at (0,500).

    B reaches at (600,0)

    Third time is (1200,-500)

    Distance = √(1200^2 +(-500)^2) = 1300 meters

  • 1 month ago

    Sure, I'd be more than glad to help you.

Still have questions? Get your answers by asking now.