Anonymous
Anonymous asked in Science & MathematicsAlternativeOther - Alternative · 1 month ago

# Can you help me to solve this math problem, please?

Two cars A and B go along two perpendicular roads with constant speeds towards the intersection (A on one road, B on the other). When A reached the intersection, the distance between the cars was 500 meters. When after that B at time T reached the intersection, the distance between the cars became 600 meters. What will be the distance between the cars when Machine A travels another 600 meters after time T?

Relevance

Every time A travels 600 meters, B travels 500 meters

When A is at (0 , 0) , B is at (-500 , 0)

When A is at (0 , 600) , B is at (0 , 0)

When A is at (0 , 1200) , B is at (500 , 0)

Does that make sense to you? Can you see why A is at the point of 1200 meters away from the intersection?

d^2 = 500^2 + 1200^2

d^2 = 100^2 * (5^2 + 12^2)

d^2 = 100^2 * (25 + 144)

d^2 = 169 * 100^2

d = 13 * 100

d = 1300

They're 1300 meters away from each other.

• Ann1 month agoReport

thank you very much!

• A reaches at (0,500).

B reaches at (600,0)

Third time is (1200,-500)

Distance = √(1200^2 +(-500)^2) = 1300 meters

• Ann1 month agoReport

thank you so much!