# I need help with this physics problem?

A 4.33 kg ball is dropped from the roof of

a building 157.2 m high. While the ball is

falling to Earth, a horizontal wind exerts a

constant force of 11.5 N on the ball.

How long does it take to hit the ground?

The acceleration of gravity is 9.81 m/s ^2

Answer in units of seconds

part 2 of 3

How far from the building does the ball hit

the ground?

Answer in units of m.

part 3 of 3

What is its speed when it hits the ground?

Answer in units of m/s.

### 1 Answer

- az_lenderLv 71 month ago
(part 1) t = sqrt(2h/g) = around 5 or 6 seconds but use a calculator.

(part 2) The horizontal acceleration "a_x" is

(11.5 N)/(4.33 kg) = around 2.7 m/s^2 but use a calculator. Then find "x", the horizontal distance, from x = (1/2)(a_x)t^2.

(part 3) Final velocity is

-(9.81 m/s^2)t j + (a_x)t I,

and use the Pythagorean Theorem to find the actual speed.