# Physics problem?

The velocity of a 382g object is sliding along a surface with a constant velocity of 3.77m/s. The coefficient of friction is 0.145. what is the net force?

### 7 Answers

- MyRankLv 62 days ago
Given,

Mass (m) = 382 grams = 0.382 kgConstant velocity (v) = 3.77 m/secCoefficient of friction (µ) = 0.145Net force (FNet) = ?We know that:-Net force (FNet) = frictional force + Normal force= FNet = µmg + ma= FNet = µmg + m(0) (∵ constant velocity)= FNet = µmg = 0.145 x 0.382 x 9.81= 0.543N∴ Net force (FNet) = 0.543N.

Source(s): http://myrank.co.in/ - oubaasLv 71 month ago
F = m*g*μ+ma = m(g*μ+a)

sincethe speed is constant, then a = 0, therefore :

F =m*g*μ = 0.382*0.145*9.806 = 0.543 N

- electron1Lv 71 month ago
F = m * a

Since the object is moving at a constant velocity, the acceleration is 0 m/s^2. This means the net force is 0 N. This means the applied force is equal in magnitude to the friction force.

Ff = 0.145 * 0.382 * 9.8 = 0.542822 N

This is the applied force.

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- oldschoolLv 71 month ago
The velocity of a 382g object is sliding along a surface with a constant velocity of 3.77m/s. The coefficient of friction is 0.145. what is the net force?

The force of friction = 0.382*9.8*0.145 = 0.5428N but if that were the only force, it would be decelerating so there must be an opposing pulling or pushing force of the same magnitude or the velocity could not be constant. The other answers are correct. When acceleration = 0, Fnet = 0

- az_lenderLv 71 month ago
If the velocity is constant, there is NO net force acting on the sliding object. The question is poorly phrased, but that's not your fault.

- Steve4PhysicsLv 71 month ago
Trick question. The net (resultant) force is zero (or else the velocity would change).