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# A 1.58g sample of C2H3X3(g) has a volume of 297mL at 1.012 atm and 35 degrees celsius. What is the molar mass of X? SOS!!?

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- pisgahchemistLv 78 months agoFavorite Answer
Unknown element ....

"A 1.58g sample of C2H3X3(g) has a volume of 297mL at 1.012 atm and 35C"

PV = nRT ............... ideal gas equation

PV = mRT / M ........ n=m/M .... m=mass, M=molar mass

M = mRT / (PV) ...... solve for M

M = 1.58g x 0.08206 Latm/molK x 308K / 1.012 atm / 0.297L

M = 132.9 g/mol ...... the molar mass of C2H3X3

Subtract the masses of carbon and hydrogen from the molar mass of the gas, and divide by 3 because there are 3 atoms of X.

(132.9 - 24 - 3) / 3 = 35.3 g/mol ..... X is chlorine

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Thank you so much, sir!! God bless you.