when the temperature of 0.0788 moles of a diatomic gas drops, its internal energy drops by -50.7 J. What was the temperature change?
- NCSLv 78 months agoFavorite Answer
ΔE = n * Cv * ΔT
You have n and ΔE.
For a diatomic gas, Cv = (5/2)R
and R = 8.314 J/mol·K
So you can compute the temperature change in K (which is the same as the temperature change in ºC, since for CHANGES, 1 K = 1 ºC).
I get ΔT = -31.0 ºC
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