# thermodynamics?

when the temperature of 0.0788 moles of a diatomic gas drops, its internal energy drops by -50.7 J. What was the temperature change?

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- NCSLv 78 months agoFavorite Answer
ΔE = n * Cv * ΔT

You have n and ΔE.

For a diatomic gas, Cv = (5/2)R

and R = 8.314 J/mol·K

So you can compute the temperature change in K (which is the same as the temperature change in ºC, since for CHANGES, 1 K = 1 ºC).

I get ΔT = -31.0 ºC

Hope this helps!

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