physics help please !!.?
A test rocket is fired vertically upward from the surface of the earth at a constant acceleration of a1 =19.0 m/s2. After t1 =35.0 s the fuel in the rocket is expended, and the rocket eventually falls back to earth
1. Find the maximum height attained by the rocket
- NCSLv 710 months agoFavorite Answer
at t = 35.0 s,
h = ½at² = ½ * 19.0m/s² * (35.0s)² = 11 638 m
and v = at = 19.0m/s² * 35.0s = 665 m/s
H = h + v²/2g = 11638m + (665m/s)² / 19.6m/s² = 34 200 m = 34.2 km
is a good approximation since gravitational acceleration is largely unaffected at this low altitude.
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