The position of a particle as a function of time is given by r =( 6.5 i^+ 2.1 j^)t2m, where t is in seconds.
I need to find what is the particle s speed at t1 = 2.9 s ?
The answer was 40 m/s
- oubaasLv 710 months ago
acceleration a = 2(6.5^2+2.1^2)^0,5
V = a*t = 5.8*6.831 = 39.62 m/sec
- VamanLv 710 months ago
r =( 6.5 i^+ 2.1 j^)t2m, where t is in seconds.
x= 6.5 t^2, dx/dt= 13 t. After t=1.9, x velocity=24.7
y=2.1 t^1, dy/dt=4.2, After 1.9, y velocity =7.98
The msgnitude of velocity = swrt(vx^2+vy^2)=sqrt(24.7^2+7.98^2)=25.95 m/s
- alexLv 710 months ago
v = dr/dt
speed = |v|