How many grams of Ammonia, NH3 can be made from 250.grams of N2(g)?

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  • 2 months ago

    Molar mass of N₂ = 14.0×2 g/mol = 28.0 g/mol

    Molar mass of NH₃ = (14.0 + 1.0×3) g/mol = 17.0 g/mol

    N₂ + 3H₂ → 2NH₃

    Mole ratio N₂ : NH₃ = 1 : 2

    Moles of N₂ = (250 g) / (28.0 g/mol) = 8.93 mol

    Moles of NH₃ = (8.93 mol) × 2 = 17.86 mol

    Mass of NH₃ = (17.86 mol) × (17.0 g/mol) = 304. g

    ====

    OR:

    (250 g N₂) × (1 mol N₂ / 28.0 g N₂) × (2 mol NH₃ / 1 mol N₂) × (17.0 g NH₃ / 1 mol NH₃)

    = 304. g

  • david
    Lv 7
    2 months ago

    N2 + 3H2 --> 2NH3

    250/28 = x/34

    x = 303.57 g ... round to 2 sig figs 3.0 x 10^2 g

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