Liam asked in Science & MathematicsPhysics · 4 months ago

A golfer hits a shot to a green that is elevated 3 m above the point where the ball is struck.?

The ball leaves the club at a speed of 14.9 m/s at an angle of 38.5° above the horizontal. It rises to its maximum height and then falls down to the green. It rises to its maximum height and then falls down to the green. Find the speed.

Update:

Please help Bill or the Old Science Guy

1 Answer

Relevance
  • NCS
    Lv 7
    4 months ago
    Favorite Answer

    Welcome to Yahoo!Answers.

    I'm not Bill or the Old Science Guy, but I can help.

    Find the FINAL speed? Well, we have the initial KE:

    KE = ½mv² = ½ * M * (14.9m/s)² = M * 111m²/s²

    When it reaches the green, it has 3 m worth of potential energy that it didn't have before (because the green is elevated):

    GPE = mgh = M * 9.8m/s² * 3m = M * 29.4m²/s²

    the final KE is

    KE' = KE - GPE = M * 111m²/s² - M * 29.4m²/s² = M * 81.6m²/s²

    and this

    KE' = ½ * M * V²

    where V is the final velocity

    so

    ½ * M * V² = M * 81.6m²/s²

    mass M cancels

    V² = 163 m²/s²

    V = 12.8 m/s ◄

    OR

    you could just use

    v² = u² + 2as = (14.9m/s)² + 2 * -9.8m/s² * 3m = 163 m²/s²

    as before.

    I THOUGHT you were going to ask "How far away does the ball land?"

    This can be done in one step using the trajectory equation:

    y = h + x·tanΘ - g·x² / (2v²·cos²Θ)

    where y = height at x-value of interest = 3 m

    and h = initial height = 0 m

    and x = range of interest = ???

    and Θ = launch angle = 38.5º

    and v = launch velocity = 14.9 m/s

    Dropping units for ease (x is in meters):

    3 = 0 + x*tan38.5º - 9.8x² / (2*14.9²*cos²38.5º)

    0 = -3 + 0.7954x - 0.0360x²

    This quadratic has roots at

    x = 4.83 m ← ball at 3 m height and rising

    and x = 17.3 m ◄ ball at 3 m height and falling

    If you find this helpful, please award Best Answer!

    • Login to reply the answers
Still have questions? Get your answers by asking now.