## Trending News

# IP A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 33 ∘ with the surface of the lawn.?

part a

If a 60.0-N force is applied along the handle of the 18-kg mower, what is the normal force exerted by the lawn on the mower?

Express your answer using two significant figures.

part b

If the angle between the surface of the lawn and the handle of the mower is increased, does the normal force exerted by the lawn increase, decrease, or stay the same?

Increases

Decreases

Stays the same

### 2 Answers

- oubaasLv 74 months agoFavorite Answer
Sin 33° = 0.545

Cos 33° = 0.839

motion equation

(m*g+F*sin 33)*μ = F*cos 33

(18*9.8+60*0.545)*μ = 60*0.839

209.1μ = 50.32

μ = 50.32/209.1 = 0.241

Fn = (18*9.8+60*0.545) = 209.1 N

if angle Θ (and therefore sin Θ) increases, then Fn increases ; if Θ increases such as sin Θ = 0.6, then Fn equates (18*9.8+60*0.6) = 212.4 N and μ' must be lower than μ.

212.4*μ' = 60*0.8

μ' = 48/212.4 = 0.226

- Login to reply the answers

- kuiperbelt2003Lv 74 months ago
the normal force will be equal to the weight of the lawn mower plus the vertical component of the applied force. Find the weight by multiplying 18 kg x 9.8 m/s/s

The vertical component of the force is 60 sin 33.

If the angle increases, then the component of applied force in the vertical direction increases, and the normal force will also increase.

- derek4 months agoReport
Will the answer be 176.4. I multiplied the numbers

- Login to reply the answers