derek asked in Science & MathematicsPhysics · 4 months ago

IP A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 33 ∘ with the surface of the lawn.?

part a

If a 60.0-N force is applied along the handle of the 18-kg mower, what is the normal force exerted by the lawn on the mower?

Express your answer using two significant figures.

part b

If the angle between the surface of the lawn and the handle of the mower is increased, does the normal force exerted by the lawn increase, decrease, or stay the same?

Increases

Decreases

Stays the same

2 Answers

Relevance
  • oubaas
    Lv 7
    4 months ago
    Favorite Answer

    Sin 33° = 0.545

    Cos 33° = 0.839

    motion equation

    (m*g+F*sin 33)*μ = F*cos 33

    (18*9.8+60*0.545)*μ = 60*0.839

    209.1μ = 50.32

    μ = 50.32/209.1 = 0.241

    Fn = (18*9.8+60*0.545) = 209.1 N

    if angle Θ (and therefore sin Θ) increases, then Fn increases ; if Θ increases such as sin Θ = 0.6, then Fn equates (18*9.8+60*0.6) = 212.4 N and μ' must be lower than μ.

    212.4*μ' = 60*0.8

    μ' = 48/212.4 = 0.226

    • Login to reply the answers
  • 4 months ago

    the normal force will be equal to the weight of the lawn mower plus the vertical component of the applied force. Find the weight by multiplying 18 kg x 9.8 m/s/s

    The vertical component of the force is 60 sin 33.

    If the angle increases, then the component of applied force in the vertical direction increases, and the normal force will also increase.

    • derek4 months agoReport

      Will the answer be 176.4. I multiplied the numbers

    • Login to reply the answers
Still have questions? Get your answers by asking now.