M asked in Science & MathematicsPhysics · 2 months ago

The figure shows a cylindrical metal shell that is coaxial with a thin wire. Both are very long, and the shell has inner radius ri and?

ri = inner radius

ro = outer radius

λi, λo = inner, outer linear charge density

Q1: To find E at r = 0.5ri , what should be substituted for λ in the cylindrical equation?

λ = _____

Q2:To find E at a radius between ri and ro, what should be substituted λ for in the cylindrical equation?

λ =_____

Q3: What is the linear charge density λi along the inner wall of the shell? (This is the charge per unit length along the length of the shell.) (formula)

λi = _____

Q4: What is the linear charge density λo along the outer wall of the shell?

λo =_____

Q5: To find E at r = 2ro , what should be substituted for λ in the cylindrical equation?

λ=_____

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1 Answer

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  • NCS
    Lv 7
    2 months ago
    Best Answer

    Not really in my wheelhouse, but here's a try:

    Q1) λ_w, since that's the enclosed charge (per unit length, for a cylinder of radius r_i)

    Q2) λ = 0 (See citation, esp. pg 5. Upshot: field is 0 within the conductor)

    Q3) λ_i = -λ_w (See citation, especially pg 3)

    Q4) λ_o = λ_w, since the total charge of the cylinder is zero ("electrically neutral")

    Q5) for all r > r_o, λ = λ_w (total enclosed charge)

    Hope this helps!

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