The figure shows a cylindrical metal shell that is coaxial with a thin wire. Both are very long, and the shell has inner radius ri and?
ri = inner radius
ro = outer radius
λi, λo = inner, outer linear charge density
Q1: To find E at r = 0.5ri , what should be substituted for λ in the cylindrical equation?
λ = _____
Q2:To find E at a radius between ri and ro, what should be substituted λ for in the cylindrical equation?
Q3: What is the linear charge density λi along the inner wall of the shell? (This is the charge per unit length along the length of the shell.) (formula)
λi = _____
Q4: What is the linear charge density λo along the outer wall of the shell?
Q5: To find E at r = 2ro , what should be substituted for λ in the cylindrical equation?
- NCSLv 72 months agoBest Answer
Not really in my wheelhouse, but here's a try:
Q1) λ_w, since that's the enclosed charge (per unit length, for a cylinder of radius r_i)
Q2) λ = 0 (See citation, esp. pg 5. Upshot: field is 0 within the conductor)
Q3) λ_i = -λ_w (See citation, especially pg 3)
Q4) λ_o = λ_w, since the total charge of the cylinder is zero ("electrically neutral")
Q5) for all r > r_o, λ = λ_w (total enclosed charge)
Hope this helps!