Chease asked in Science & MathematicsPhysics · 11 months ago

A bug moves at a rate of 9 meters a second. How far does it travel in 0.1 seconds and how long does it take for it to go 4 meters?

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  • 11 months ago
    Favorite Answer

    To solve these two problems, use the following equation.

    d = v * t

    9 = v * 0.1

    v = 90 m/s

    This is constant.

    4 = 90 * t

    t = 4 ÷ 90

    The time is approximately 0.044 seconds. This is 4/9th of the original time. I hope this is helpful

  • oubaas
    Lv 7
    11 months ago

    distance d = V*t = 9.0*0.1 = 0.9 meters

    time t = d'/V = 4.0/9 = 4/9 of sec ( ≅ 0.(4) )

  • 11 months ago

    Geez, that is one fast bug, must be in flight.

  • 11 months ago

    0.9m

    4/9 s

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  • 11 months ago

    I smash it so it don't move

  • Anonymous
    11 months ago

    speed = distance / time

    Very easy calc.

  • Greg
    Lv 7
    11 months ago

    9 x 0.1

    4/9

    Just that simple.

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