Can someone please answer these or show me how to work them?
- NCSLv 73 months agoFavorite Answer
v² = u² + 2gh
leads to (when final velocity u = 0)
maximum height h = v² / 2g = (44m/s)² / 2*9.8m/s² = 99 m
You could go through the calculations using the preceding formula, or you could reason that when the velocity is half the original velocity, then the KE is one fourth of the original KE. That means that the PE is 3/4 of the final PE, and so the height is 3/4 of the final height.
h' = 3h/4 = 74 m
Simple geometry. When the angle is given w/r/t horizontal (as in this case and most cases), the "cos" function gives the horizontal component:
x = 178m * cos(-21º)
y = 178m * sin(-21º)
(north) y = 4.77km * sin(14.7º)
(east) x = 4.77km * cos(14.7º)
If you find this helpful, please award Best Answer!
- NotLv 43 months ago
No, look on the pages just before in the same chapter.