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# U substitution?

integral (x^2+2) sin(2x^3 + 6x)dx

i set u as 2x^3 + 6x.

du is 6x^2 + 6.

Do i factor it more or dx=du/ 6x^2 + 6

Update:

its (x^2 +1) not (x^2+2)

### 1 Answer

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- PopeLv 711 months agoFavorite Answer
You were doing fine. I would not try to factor anything. Just proceed with the substitutions.

u = 2x³ + 6x

du/dx = 6x² + 6

du = (6x² + 6) dx

∫ (6x² + 6)sin(2x³ + 6x) dx = ∫ sin(u) du

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oops sorry, i was being a dummy again. (x^2 + 1)/6x^2 + 6 = 1/6 you are absolutely correct sorry