integral (x^2+2) sin(2x^3 + 6x)dx
i set u as 2x^3 + 6x.
du is 6x^2 + 6.
Do i factor it more or dx=du/ 6x^2 + 6
its (x^2 +1) not (x^2+2)
- PopeLv 711 months agoFavorite Answer
You were doing fine. I would not try to factor anything. Just proceed with the substitutions.
u = 2x³ + 6x
du/dx = 6x² + 6
du = (6x² + 6) dx
∫ (6x² + 6)sin(2x³ + 6x) dx = ∫ sin(u) du