Anonymous
Anonymous asked in Science & MathematicsChemistry · 3 months ago

# What is the volume in liters of 3.55 kg of ethylene glycol? With a density of 1.1 g/cm^3.?

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• Dr W
Lv 7
3 months ago

in chemistry class.. we do our calculations via "factor label method".. aka.. "dimensional analysis" to chemistry students. I cover that in my answer here

in chemistry class.. we use "significant figures".. aka... "sig figs".. to indicate the precision of our results. I cover that in my answer here

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this problem

.. 3.55kg E.G... .. 1000g... .. 1 cm³.. . ..... 1 L

---- ---- ---- ---- x ----- ----- x ----- ----- x ----- ----- = 3.2L

.. ... .. . 1.. .. .. ... . 1 kg... . ... 1.1g.. .. . 1000cm³

which you calculate by entering

.. 3.55 / 1.1 =

in your calculator and rounding to 2 sig figs

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typically, we would write that as

.. 3.55kg * (1000g / 1kg) * (1cm³ / 1.1g) * (1L / 1000cm³) = 3.2L

when it's difficult to draw out the unit factors because of formatting.

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now.. an alternate approach is to read that density as 1.1 kg / L... in which case

.. 3.55kg * (1 L / 1.1kg) = 3.2L

• Born Yesterday
Lv 7
3 months agoReport

Thank you. I assumed Algebra was the obstacle and
dashed something off.

• 3 months ago

1.1 g/cm^3 = 1.1 kg/L

(3.55 kg) / (1.1 kg/L) = 3.2 L

• Roger the Mole
Lv 7
3 months agoReport

I like and use dimensional analysis a great deal, but there exist topics in chemistry besides dimensional analysis.

• 3 months ago

3.55/0.0011 =

3227.27 cm^3