# physics question??

The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 4.10 cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin

### 1 Answer

- billrussell42Lv 77 months agoFavorite Answer
only one question please

this is vector arithmetic.

for the left charge

Ex = 2µk/r² pointed right

Ey = 0

for the right charge

Ex = 3µk/r² pointed right

Ey = 0

for the top charge

Ex = 0

Ey = 5µk/r² pointed up

now add up the x and y components

Ex = 5µk/r² pointed right

Ey = 5µk/r² pointed up

E = √(Ex² + Ey²)

E = 5µk√2/r²

E = (5e-6)(9e9)√2/(0.041)² = 3.79e7 v/m

but check the math

other is similar.

Electric field

The strength or magnitude of the field at a given point

is defined as the force that would be exerted on a

positive test charge of 1 coulomb placed at that point;

the direction of the field is given by the direction of

that force.

E = F/Q = kQ/r²

Q = F/E F = QE

in Newtons/coulomb OR volts/meter

k = 1/4πε₀ = 8.99e9 Nm²/C²

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