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Sana asked in Science & MathematicsPhysics · 7 months ago

physics question??

The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 4.10 cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin

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  • 7 months ago
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    only one question please

    this is vector arithmetic.

    for the left charge

    Ex = 2µk/r² pointed right

    Ey = 0

    for the right charge

    Ex = 3µk/r² pointed right

    Ey = 0

    for the top charge

    Ex = 0

    Ey = 5µk/r² pointed up

    now add up the x and y components

    Ex = 5µk/r² pointed right

    Ey = 5µk/r² pointed up

    E = √(Ex² + Ey²)

    E = 5µk√2/r²

    E = (5e-6)(9e9)√2/(0.041)² = 3.79e7 v/m

    but check the math

    other is similar.

    Electric field

    The strength or magnitude of the field at a given point

    is defined as the force that would be exerted on a

    positive test charge of 1 coulomb placed at that point;

    the direction of the field is given by the direction of

    that force.

    E = F/Q = kQ/r²

    Q = F/E F = QE

    in Newtons/coulomb OR volts/meter

    k = 1/4πε₀ = 8.99e9 Nm²/C²

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