Anonymous
Anonymous asked in Science & MathematicsChemistry · 6 months ago

The time to transfer 1.25 x 103 C using a current of 7.00 A ?

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  • Umar
    Lv 7
    6 months ago

    Q = i x t

    1.25 x 10^3C = 7A x t

    t = 178.57sec ~ 3 min

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  • 6 months ago

    Unit factor method .... use the current as a conversion factor.

    Current is the rate of flow of charge, and given in coulombs per second. A current of 7 amperes is 7 coulombs per second

    1250 C x (1 s / 7.00 C) = 179 s

    ============

    You may eventually have to relate this to a chemical reaction, and you may run across a faraday. A faraday is the amount of charge on a mole of electrons:

    ...... 1F = 96,485C.

    Like, "How many grams of copper are produced from Cu2+ ions in a cell with a current of 7.00 amperes running for 45.0 minutes?"

    45.0 min x (60 s / 1 min) x (7.00 C / 1s) x (1 mol e- / 96485C) x (1 mol Cu / 2 mol e-) x (63.55g Cu / 1 mol Cu) = 6.22g Cu

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  • Anonymous
    6 months ago

    1 amp = 1 C/sec

    1.25 * 10^3 C / 7 C/sec = time in seconds.

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