Anonymous
Anonymous asked in Science & MathematicsMathematics · 12 months ago

Consider a brick of dimensions, length = 8.0 in (in = inch), width = 4.0 in, and thickness = 3.0 in.?

Consider a brick of dimensions, length = 8.0 in (in = inch), width = 4.0 in, and thickness = 3.0 in. What’s the maximum number of bricks that can be stored, one layer thick, on a floor of width = 8.0 ft and length = 16.0 ft.?

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  • Anonymous
    12 months ago

    This is a slightly trick question: so one has to read it carefully. There is a reason why they give all three dimensions. They are expecting the unwary to fall into the trap of thinking that the bricks have to be laid on their largest face. But it doesn't say that.

    To maximise your bricks in one layer, stand them on the smallest face (4 x 3 inches). In a square foot of floor space that means 12 bricks fit exactly. There are 128 square feet available. So the maximum in one layer is 1,536.

  • 12 months ago

    576...way too simple ..8x4=32..forget the height ..8x16=132.x144=18,432...divide by 32=576

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