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# Chem help?

The acid in an automobile battery (a solution of sulfuric acid) has a density of 1.2 g/cm³. How many sulfuric acid particles are in 2.00 x 10² mL of this acid?

### 2 Answers

- davidLv 76 months agoFavorite Answer
200. mL = 200. cm^3

1.2 X 200 = 240 g

200 g water -- 40 g Acid

40 X (6.02x10^23)/98 = 2.46x10^23 formula units H2SO4

- pisgahchemistLv 76 months ago
Amount of H2SO4 in battery acid ....

What we know:

volume of acid = 200. mL

Density of acid = 1.20g / mL

Mass of solution = 240. g

Not all of the volume of solution can be attributed to water, some is H2SO4.

Density of H2SO4 = 1.83 g/mL

Density of water = 1.00 g/mL

Let x = volume of H2SO4, then volume of H2O is (200 - x)

1.83 g/mL(x mL) + (1.00g/mL)(200-x)mL = 1.2g/mL x 200.mL = 240g

(1.83x)g + 200g - (1.00x)g = 240g

(0.83x)g = 40.g

x = 48mL ...................... the volume of H2SO4 in the mixture

48mL H2SO4 x (1.83 g H2SO4 / 1 mL H2SO4) x (6.022x10^23 molecules H2SO4 / 98.1g H2SO4) = 5.39x10^23 molecules H2SO4

Check:

48 mL H2SO4 + 152 mL water = 200 mL ........ assuming vols are additive

48 mL H2SO4 x 1.83 g/mL + 152 mL x 1.00g/mL = 240g

density of mixture = 240g / 200 mL = 1.2 g/mL

The solution contains 88 grams of H2SO4 and is within right range.

48 mL x (1.83g / 1mL) x (1 mol / 98.1g) / 0.200L = 4.48 M H2SO4 ...

Battery acid is between 4.2 and 5.0M, and the density is between 1.25 and 1.30 g/mL. David's answer give a molarity of 2.0M, far below that of battery acid.- Login to reply the answers

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