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Based on the given figure, find the following values of trigonometric functions.?

Answer must be in a radical in simplified form.

Sin A

Sin B

Cos A

Cos B

Tan A

Tan B

If you can show me how to work this out, I will most likely be able to do the other problems like this. Thanks

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  • 9 months ago
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    Find the hypotenuse of the right triangle

    x² = 8² + 12²

    x² = 64 + 144

    x² = 208

    x = √208

    x = 4√13

    hyp = 4√13

    --------------------

    Sin A = opp/hyp

    SinA = 12/(4√13)

    SinA = 3/√13

    SinA = (3√13) / 13 <–––––

    ----------------------

    SinB = opp/hyp

    SinB = 8 / (4√13)

    SinB = 2/√13

    SinB = (2√13) / 13 <–––––

    ---------------------

    CosA = adj/hyp

    CosA = 8/(4√13)

    CosA = 2/√13

    CosA = (2√13) / 13 <–––––

    -------------------

    CosB = adj/hyp

    CosB = 12/(4√13)

    CosB = 3/√13

    CosB = (3√13) / 13 <–––––

    -------------------

    TanA = opp/adj

    TanA = 12/8

    TanA = 3/2 <––––––

    -----------------

    TanB = opp/adj

    TanB = 8/12

    TanB = 2/3 <––––––

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