# One cubic centimeters (1.0 cm^3) of mercury has a mass of 0.014 kg at 25 degrees C , find the mass of 3.5m^3 of mercury at 25 degrees C?

Relevance

1 cubic meter = 10^6 cubic cm

0.014 kg/cm^3 * 3.5 * 10^6 cm^3 =>

3.5 * 0.014 * 10^6 kg =>

3.5 * 1.4 * 10^(-2) * 10^(6) kg =>

3.5 * 1.4 * 10^(4) kg =>

(7/2) * (7/5) * 10^4 kg =>

(49/10) * 10^4 kg =>

4.9 * 10^4 kg

49000 kg

• you need to learn and use "factor label method"... aka... "dimensional analysis" to you chem students

I cover it in my answer here

do yourself a favor and READ that link. DA is the backbone of ALL modern chemistry calculations and if you learn it and learn to apply it by practicing, you WILL get better grades in general chemistry.

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this problem

.. 3.5 m³ * (100cm / 1m)³ * (0.014kg / 1cm³) = 4.9x10^4 kg

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you calc it by entering

.. 3.5 * 100^3 * 0.014 =

in your calculator and rounding to 2 sig figs

• According to the information above, at 25˚C, the mass of one cubic centimeters of mercury is 0.014 kg. This is the density of mercury at this temperature. To determine the mass of the mercury, multiply the density by the volume. The first step is to convert cubic meters to cubic centimeters.

1m= 100 cm

1 m^3 = 1 * 10^6 cm^3

V = 3.5 * 10^6 cm^3

Mass = 0.014 * 3.5 * 10^6 = 4.9 * 10^4 kg