Simplify this maths problem?
I tried it and got 81/y^3 (0.04y^8)
What have I done wrong?
- ComoLv 74 months ago
( 18/y^4 ) x (y^8/25)
( 18/25 ) y^4
- 4 months ago
y8/y⁴ (81/25 ) = y ^(8-4) * 81/25
- JOHNLv 74 months ago
- sepiaLv 74 months ago
(-3/y)^4 (1/5 y^4)^2
= 81y^8 / (25 y^4)
= 81y^4 / 25
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- Jim MoorLv 74 months ago
81/y^4 (0.04y^8) is ok as far as it goes, but it could go further
81/y^4 * y^8 / 25
- PinkgreenLv 74 months ago
- KrishnamurthyLv 74 months ago
- llafferLv 74 months ago
First, keep fractions as fractions.
Then your y's can be combined from the first factor and the second factor.
You started correctly, but needed to finish things up.
- LônLv 74 months ago
Do each separately first....
(81/y^4) x (y^8/25) ......now multiply
81y^8 / 25y^4