Anonymous
Anonymous asked in Science & MathematicsPhysics · 6 months ago

# I need help with physics homework?

A 45 kg object sits on top of a 200 m high cliff on the surface of the Earth. Acceleration of gravity is the standard value , rounded to the nearest tenth)

A) If the reference line is at the bottom of the cliff, how much GPE does the object possess?

B) If the reference line is at top of the cliff, how much GPE does the object possess?

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A) If the reference line is at the bottom of the cliff, how much GPE does the object possess?

GPE = m*g*(h-ho) = 45*(200-0)*9.8/1000 = 88.200 kjoule

B) If the reference line is at top of the cliff, how much GPE does the object possess?

zero , since h-ho is zero

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• A) If the reference line is at the bottom of the cliff, how much GPE does the object possess?

GPE = m * g * h

I will use 9.8 m/s^2 for the acceleration due to gravity.

GPE = 45 * 9.8 * 200 = 88,200 J

B) If the reference line is at top of the cliff, how much GPE does the object possess?

If the reference line is at top of the cliff, h is 0 meters. The means the GPE is 0 joule. I hope this is helpful for you.

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• In a homogenous gravitational field g, the gravitational potential energy of a mass m, at height h above its reference level, is mgh.

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• A 45 kg object sits on top of a 200 m high cliff on the surface of the Earth. Acceleration of gravity is the standard value , rounded to the nearest tenth) A) If the reference line is at the bottom of the cliff, how much GPE does the object possess? B) If the reference line is at top of the cliff, how much GPE does the object possess

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