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# Physics question?

A 40 kg object falls 500m from rest on a planet exactly like earth, except it has no atmosphere. If energy of the object is conserved, how fast is the object traveling at the end of its fall. Round answer to nearest whole number and put it in the following blank (include units)

### 3 Answers

- oubaasLv 711 months agoFavorite Answer
V = √2gh = √1000*9.806 = 10√98.06 ≅ 100 m/sec

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- Anonymous11 months ago
Conserved: Initial energy = final energy.

Initial energy is potential energy due to gravity (mass * g * height). Initial velocity is 0. Initial height is "h"

Final energy is kinetic due to motion ((1/2)*mass*(velocity^2)). Final velocity is "v". Final height is 0.

PE = KE

Potential energy due to gravity = kinetic energy due to motion

m*g*h = (1/2)*m*(v^2)

v = √(2gh)

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- Anonymous11 months ago
PE = KE

Conservation of energy, substitute and solve

Hint, the mass doesn't matter if there is no air resistance.

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