If y varies directly as x and inversely as the square of z, and y=8 when x=4 and z=3, find y when x=6 and z=2?
3 Answers
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 ComoLv 710 months ago

y = k x / z²
k = y z² / x = 8 x 9 / 4 = 18
y = 18 x 6 / 4
y = 27
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 TomVLv 710 months ago
y = kx/z²
8 = k(4/9) → k = 72/4 = 18
y = 18x/z²
y = 18(6/4) = 27
ans: 27
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 derframLv 710 months ago
y = k(x/z²)
8 = k(4/3²)
8 = k(4/9)
k = 18
y = k(x/z²)
y = 18[6/(2)²]
y = 18(6/4)
y = 27
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