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- AshLv 75 months ago
(a) h=3 , so h≠5 then we consider f(x) = (x²-25)/(x-5)

f(3) = (3²-25)/(3-5) = -16/-2 = 8

(b) h=0, so h≠5 then we consider f(x) = (x²-25)/(x-5)

f(0) = (0²-25)/(0-5) = -25/-5 = 5

(c) h=5, then we consider f(x) = 2

f(5) = 2

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