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- 10 months agoFavorite Answer
f(-2.8) = 4

f(1.2) = 0

f(pi) = -2

f(-1) = 2

f(2) = -1

f(-pi) = 5

I can forgive crappy notation from a student, but this problem is setup by a moron. Is that a division between f(-1) and f(2)? If so, then do they want it to be f(-1) / (f(2) * f(-pi)) or do they want f(-1) * f(-pi) / f(2)? It matters.

sqrt(4 + 0) - (-2)^2 + 2 / ((-1) * 5) =>

sqrt(4) - 4 + 2 / (-5) =>

2 - 4 - 2/5 =>

-2 - 2/5 =>

-12/5

or

sqrt(4 + 0) - (-2)^2 + 2 * 5 / (-1) =>

2 - 4 + 10/(-1) =>

2 - 4 - 10 =>

2 - 14 =>

-12

One of those is right. Bring up the crappy notation with your teacher or professor.

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- RealProLv 710 months ago
f(-2.8) = 4

f(1.2) = 0

f(pi) = -2

f(-1) = 2

f(2) = -1

f(-pi) = 5

Or you can use 1 - floor(x)

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