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samuel asked in Science & MathematicsPhysics · 10 months ago

Physics question?

Two objects are charged and their centers are separated by 28.6 cm. Object A is charged to 34 nC and object B is charged to 38 nC. What is the magnitude of the electrostatic force between them?

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  • 10 months ago
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    The following equation is used to solve this problem.

    F = k * Q1 * Q2 ÷ d^2

    I use 9 * 10^9 for k. The unit of the charge must be in coulombs, and the unit of distance must be in meters.

    Q1 = 3.4 * 10^-8 C

    Q2 = 3.8 * 10^-8 C

    d = 0.286 m

    F = 9 * 10^9 * 3.4 * 10^-8 * 3.8 * 10^-8 ÷ 0.286^2 = 1.1628 * 10^-5 ÷ 8.1796 * 10^-2

    The force is approximately 1.42 * 10^-4 N.

  • 10 months ago

    Coulomb's law, force of attraction/repulsion

    F = kQ₁Q₂/r²

    Q₁ and Q₂ are the charges in coulombs

    F is force in newtons

    r is separation in meters

    k = 8.99e9 Nm²/C²

    F = (9e9)(34e-9)(38e-9) / 0.286²

    you can do the math.

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