# Physics question?

Two objects are charged and their centers are separated by 28.6 cm. Object A is charged to 34 nC and object B is charged to 38 nC. What is the magnitude of the electrostatic force between them?

### 2 Answers

- electron1Lv 710 months agoFavorite Answer
The following equation is used to solve this problem.

F = k * Q1 * Q2 ÷ d^2

I use 9 * 10^9 for k. The unit of the charge must be in coulombs, and the unit of distance must be in meters.

Q1 = 3.4 * 10^-8 C

Q2 = 3.8 * 10^-8 C

d = 0.286 m

F = 9 * 10^9 * 3.4 * 10^-8 * 3.8 * 10^-8 ÷ 0.286^2 = 1.1628 * 10^-5 ÷ 8.1796 * 10^-2

The force is approximately 1.42 * 10^-4 N.

- billrussell42Lv 710 months ago
Coulomb's law, force of attraction/repulsion

F = kQ₁Q₂/r²

Q₁ and Q₂ are the charges in coulombs

F is force in newtons

r is separation in meters

k = 8.99e9 Nm²/C²

F = (9e9)(34e-9)(38e-9) / 0.286²

you can do the math.

- Login to reply the answers

Please feel free to ask for my help in the future!