scott asked in Science & MathematicsPhysics · 6 months ago

If a 20 kg of mass, m, is attached to the above spring in problem 20 (spring constant k), what will the frequency of oscillation, f, be?

A spring is 0.10 m long when no force is applied to it. When 4 N pull is applied to the spring, it stretches to a total length of 0.15 m. What is the spring constant for this spring?

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  • 6 months ago
    Favorite Answer

    f = 1/(2 * π) * √(k/m)

    The first step is solve problem 20 to determine the spring constant.The unit of the spring constant is N/m The first step is to determine the increase of the length.

    ∆ L = 0.15 – 0.10 = 0.05 meter

    k = 4 ÷ 0.05 = 80 N/m

    Now we can use the spring constant to calculate the frequency.

    k/m = 80/20 = 4

    √(k/m) = 2

    f = 1/2π * 2

    The frequency is 1/π. This is approximately 0.32 Hz. I hope this is helpful for you.

    • electron1
      Lv 7
      6 months agoReport

      Thank you for the best answer award.

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  • NCS
    Lv 7
    6 months ago

    1/

    spring constant k = force / elongation = 4N / 0.05m = 80 N

    21/

    plug in values and get

    f = 0.32 Hz

    If you find this helpful, please award Best Answer. You get points too!

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