Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10ms^-2.?
Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10ms^-2.
An electric motor is used to raise the elevator with a full load from the ground floor to the third floor, 9 m higher, in 30 s. Calculate the total energy needed.
- Andrew SmithLv 711 months agoFavorite Answer
The speed is not needed for the total energy required if any gain in kinetic energy at the beginning is used in permitting the elevator to coast to a stop.
E = mgh = ( 700+600)*10 * 9 = 117 kJ approximately.
- Anonymous11 months ago
energy needed E = m*g*Δh = (700+600)*9.806*9/1000 = 114.7 kjoule
power P = E/t = 114.7/30 = 3.82 kw