Anonymous
Anonymous asked in Science & MathematicsPhysics · 6 months ago

Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10ms^-2.?

Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10ms^-2.

An electric motor is used to raise the elevator with a full load from the ground floor to the third floor, 9 m higher, in 30 s. Calculate the total energy needed.

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  • 6 months ago
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    The speed is not needed for the total energy required if any gain in kinetic energy at the beginning is used in permitting the elevator to coast to a stop.

    E = mgh = ( 700+600)*10 * 9 = 117 kJ approximately.

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  • Anonymous
    6 months ago

    energy needed E = m*g*Δh = (700+600)*9.806*9/1000 = 114.7 kjoule

    power P = E/t = 114.7/30 = 3.82 kw

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