Calculate the amount of heat which must be removed from 400 kg fish.....?
Calculate the amount of heat which must be removed from 400 kg fish, if it enters a freezer room at 15 degrees *c and is pulled down to -18 deg Celsius.
Must show all working.
Fomula:
Q=mc^t
Q=mL
Specific heat of fish above freezing = 1.95 kJ/kgk
Specific heat of fish below freezing = 1.10 kJ/kgk
Latent heat- 110 kJ/kg
2 Answers
Relevance
- Anonymous4 months ago
3 calculations assuming you treat the fish as an equivalent mass of water.
cool the fish to freezing, Q = mass * specific heat * temperature change from 15C to 0C
freeze the fish, Q = mass * latent heat
cool the fish from freezing to -18C, Q = mass * specific heat * temperature change from 0C to -18C
Add up the 3 numbers.
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