Given the equation: Zn(s) + 2HCl(aq)---> ZnCl2(aq) + H2(g). How many grams of Zn will be required to produce 5.85L of H2 gas at STP?
- Roger the MoleLv 710 months agoFavorite Answer
(5.85 L H2) / (22.414 L/mol) x (1 mol Zn / 1 mol H2) x (65.380 g Zn/mol) = 17.1 g Zn
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