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# How many mL of 0.406 M NaOH solution are required to completely titrate 32.84 mL of 0.119 M HNO3 solution?

Select one:

a. 9.63

b. 112

c. 680

d. 0.00159

### 2 Answers

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- pisgahchemistLv 76 months ago
Titration ....

The calculations for a titration are just like the calculations for any other situation involving solutions. Use the unit-factor method (aka dimensional analysis).

HNO3(aq) + NaOH(aq) --> NaNO3(aq) + HOH(l)

32.84 mL ......??? mL

0.119M ......... 0.406M

0.03284L x (0.119 mol HNO3 / 1L) x (1 mol NaOH / 1 mol HNO3) x (1L / 0.406 mol NaOH) = 0.00963L ... or .... 9.63 mL of NaOH

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- GodLv 76 months ago
v x M = v x M

v x 0.406 = 32.84 x 0.119

v = (32.84 x 0.119)/0.406 = 9.63mL

Therefore, (a) is correct

- pisgahchemistLv 76 months agoReport
NO, NO, NO ..... Just because you've forced the "dilution equation" into a situation to calculate a titration, doesn't make it a good idea. It may work some of the time, but not all of the time.

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