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# Mathematics?

Sam invested $2150, part of it at 6 percent and the rest at 8 percent yearly interest. The yearly income on the 8 percent investment was $22 more than twice the income from the 6 percent investment. How much did he invest at each rate?

investment at 6 percent

investment at 8 percent

### 3 Answers

- alexLv 712 months ago
Hint:

Let x be the part at 6%

then the part at 8% is (2150 - x)

set up an equation then solve for x

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- Mike GLv 712 months ago
Let x be the amount invested at 6%

Interest accrued at 6% = 0.06*x

Interest accrued at 8% = 0.08*(2150-x)

0.08*(2150-x) = 0.12x+22

150 = 0.2x

x = 750

$750 at 6%

$1400 at 8%

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- L. E. GantLv 712 months ago
Let x be the part at 6%

then the part at 8% is 2150 - x

so 0.08* (2150 -x) = 22 + 2*0.6*x

==> 2150 * 8/100 - 8x/100 = 22 + 12x/100

==>2150 * 8 -8x = 2200 +12x

==> 15000 = 20x

==> x = 750

So 750 at 6% and (2150-750) = 1400 at 8%

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