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# The specific heat of gold is 0.129 J/g^oC} If a 32.76 g sample of gold at 35 oC is heated to 84 oC,?

how many joules of energy were absorbed?

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- 6 months agoFavorite Answer
Q = m * c * dT

m = 32.76 g

dT = 84 - 35 = 49 C

c = 0.129 J/(g * C)

Q = 32.76 * 49 * 0.129 Joules

Q = 207.07596

Q = 207.1 Joules

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