The specific heat of gold is 0.129 J/g^oC} If a 32.76 g sample of gold at 35 oC is heated to 84 oC,?

how many joules of energy were absorbed?

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    Q = m * c * dT

    m = 32.76 g

    dT = 84 - 35 = 49 C

    c = 0.129 J/(g * C)

    Q = 32.76 * 49 * 0.129 Joules

    Q = 207.07596

    Q = 207.1 Joules

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