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# By what factor is the energy requirement to evaporate 75g of water at 100oC greater than the energy required to melt 75g of ice at 0oC?

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- billrussell42Lv 75 months agoFavorite Answer
I already answered this.

2256/334 = 6.75

specific heat of water is 4.186 kJ/kgC = 4.186 J/gC

= 1 calorie/gC = 5.375 J/mol·K = 1 Btu/lb-F

specific heat of ice is 2.06 kJ/kgC = 2.06 J/gC

specific heat of steam is 2.1 kJ/kgK = 2.1 J/gK

heat of fusion of ice is 334 kJ/kg = 334 J/g

heat of vaporization of water is 2256 kJ/kg = 2256 J/g

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