Best Answer:
Using physics, the only thing that can be determined is the speed the glider must have to orbit the earth. For an object to orbit the earth, the centripetal force must be equal to the Universal gravitational force.

Fc = m * v^2 ÷ r

Fg = G * M * m ÷ r^2

m * v^2 ÷ r = G * M * m ÷ r^2

v^2 = G * M ÷ r

v = √(G * M ÷ r)

G * M = 6.67 * 10^-11 * 5.98 * 10^24 = 3.98866 * 10^14

r is the distance from the center of the earth to the glider. As I looked through the intent, I found that the average height of Mount Everest is 8,848 meters. The radius of the earth is 6.38 * 10^6 meters.

r = 8,848 + 6.38 * 10^6 = 6.388848 * 10^6 meters.

v = √(3.98866 * 10^14 ÷ 6.388848 * 10^6)

The velocity is approximately 7,902 m/s. If rocket could increase the velocity of the rocket from 0 m/s to approximately 7,902 m/s, the glider would orbit the earth. I hope this is helpful for you.

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