Anonymous
Anonymous asked in Science & MathematicsChemistry · 6 months ago

Can someone help with this Chemistry question?

What is ΔE for the reaction, in units of kJ/mol?

1.11 × 10-3 mol sucrose

ΔT = 2.14 °C

qwater = 5.37 kJ

qcal = 0.898 kJ

2 Answers

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  • 6 months ago

    q = 5.37 kJ + (2.14º)(0.898 kJ/deg = 5.37 kJ + 1.92 kJ = 7.29 kJ

    7.29 kJ/1.11x10^-3 moles = 6568 kJ/mole = 6570 kJ/mole

    • Dr W
      Lv 7
      6 months agoReport

      that would be incorrect if the rxn is combustion and incorrect for anything else.

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  • Dr W
    Lv 7
    6 months ago

    elaborate please

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