Anonymous
Anonymous asked in Science & MathematicsPhysics · 7 months ago

physics help!?

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question is in pic

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    v(t) = 200 m/s - 10 m/s^2 * t seconds

    v(t) = 0

    0 = 200 - 10t

    0 = 20 - t

    t = 20

    It's going to take 20 seconds to stop, at a minimum

    s(t) = int(v(t) * dt) = 200t - 5t^2 + C

    s(0) = 0

    s(t) = 200t - 5t^2

    s(20) = 200 * 20 - 5 * 20^2 = 20^2 * (10 - 5) = 400 * 5 = 2000

    It'll need to be 2000 meters long

    You need to accelerate from 0 m/s to 82.1 m/s in a space of 2000 meters

    a(t) = a

    v(t) = int(a * dt) = at + C

    v(0) = 0

    v(t) = at

    s(t) = (1/2) * a * t^2 + C

    s(0) = 0

    s(t) = (1/2) * a * t^2

    v(k) = 82.1

    s(k) = 2000

    82.1 = a * k

    2000 = (1/2) * a * k^2

    4000 = a * k^2

    4000 / 82.1 = (a * k^2) / (a * k)

    40000 / 821 = k

    82.1 = a * k

    82.1 = 40000a / 821

    82.1 * 821 / 40000 = a

    821 * 821 / 400000 = a

    a = 1.6851025

    You need a minimum acceleration of 1.69 m/s^2

    48.7 seconds will elapse

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