MATH HELP? asap please!! which restriction is appropriate for the variable? 3y^2-3y/y+1 answer options below !!!?

answer options:

a. y =/ 1

b. y =/ 3

c. no restrictions are needed

d. y =/ -1

3 Answers

Relevance
  • ted s
    Lv 7
    6 months ago
    Favorite Answer

    obviously d) .................................{ but as typed it should be y ╪ 0 }...use (..) when needed !!!

    • Login to reply the answers
  • 6 months ago

    D.

    y cannot = -1 because that causes division by zero

    • Login to reply the answers
  • 6 months ago

    3y^2 - (3y/y) + 1 = 3y^2 - 3 + 1 = 3y^2 - 2, note that y can't be 0

    Or did you mean:

    (3y^2 - 3y) / (y + 1), note that y can't be -1, which I think answer (d) was meant to say.

    • Login to reply the answers
Still have questions? Get your answers by asking now.