An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 31.3 m/s?

An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 31.3 m/s, it then flies a further distance of 40500 m and afterwards its velocity is 41.1 m/s. Find the airplane\ s acceleration and calculate how much time elapses while the airplane covers those 40500 m.

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  • 6 months ago

    To explain the method, here is the same problem but with different values.

    An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 30.0 m/s, it then flies a further distance of 11100 m and afterwards its velocity is 40.0 m/s. Find the airplane’s acceleration and calculate how much time elapses while the airplane covers those 11100 m.

    For constant acceleration we can use the standard formula:

    v² = u² + 2as

    where u = initial velocity, v = final velocity, s = displacement and a = acceleration.

    Taking east as positive:

    40.0² = 30.0² + 2a*11100

    a = (1600 - 900)/22200 = 0.0315315 m/s² = 0.0315 m/s² to 3 sig. figs.

    Notes:

    Round answer to 3 sig. figs to match data supplied.

    You may be required to give the acceleration’s direction (as acceleration is a vector). In this case the answer would be 0.0315m/s² east as we have a positive value.

    To find time use

    v = u + at

    40.0 = 30.0 + 0.0315315t

    t = (40.0 – 30.0)/0.0315315 = 317s

    Now you can use the same method with your own figures.

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  • joe
    Lv 6
    6 months ago

    Do your own homework!

    Best wishes

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