Anonymous
Anonymous asked in Science & MathematicsChemistry · 6 months ago

2NH3(g)↽−−⇀3H2(g)+N2(g) the equilibrium concentrations were found to be [NH3]=0.250 M, [H2]=0.440 M, and [N2]=0.750 M.?

Update:

What is the equilibrium constant for this reaction?

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  • 6 months ago

    Equilibrium question ......

    2NH3(g) <==> 3H2(g) + N2(g) ................ Keq = ???

    0.250M........... 0.440M..0.750M ............... at equilibrium

    Keq = [H2]³[N2] / [NH3]²

    Keq = (0.440)³(0.750) / (0.250)²

    Keq = 1.02

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