Anonymous
Anonymous asked in Science & MathematicsPhysics · 7 months ago

# An object starts from rest and covers 60m in 8s. Find its average velocity.?

Update:

object moving in straight line-sorry forgot to add :|

Update 2:

and uniform acceleration... :#

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• Given,

Initial Velocity (u) = 0 m/sec

Time (t) = 8 sec

Distance (d) = 60 m

Average Velocity (Vavg) =?

We know that,

Average Velocity (Vavg) = Total distance travelled/ Total time taken

= 60m/ 8 sec = 7.5 m/ sec

Now, the objects velocity at 8 sec will be,

Average Velocity (Vavg) = [v + u]/ 2 = [v + 0]/2

7.5 m/sec = v/2

v = (7.5 x 2) m/sec = 15 m/sec

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• Vav = d/t = 60/8 = 15/2 = 7.5 m/sec

peak speed Vpk = Vav*2 = 15.0 m/sec

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• To determine the average velocity, divide the distance by the time.

Average velocity = 60 ÷ 8 = 7.5 m/s

Let’s use the following equation to determine the object’s velocity at 8 seconds.

Average velocity = ½ * (vi + vf), vi = 0

½ * vi = 7.5

vi = 15 m/s

During the 8 seconds, its velocity increases from 0 m/s to 15 m/s. Let’s use the following equation to determine the acceleration.

vf = vi + a * t, vi = 0

15 = a * 8

a = 1.875 m/s^2

I hope this is helpful for you.

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• 60 m / 8s = 7.5 m/s

Average speed is total distance divided by total time. And since this is straight line motion, average velocity is the same.

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