An object starts from rest and covers 60m in 8s. Find its average velocity.?
object moving in straight line-sorry forgot to add :|
and uniform acceleration... :#
- MyRankLv 67 months ago
Initial Velocity (u) = 0 m/sec
Time (t) = 8 sec
Distance (d) = 60 m
Average Velocity (Vavg) =?
We know that,
Average Velocity (Vavg) = Total distance travelled/ Total time taken
= 60m/ 8 sec = 7.5 m/ sec
Now, the objects velocity at 8 sec will be,
Average Velocity (Vavg) = [v + u]/ 2 = [v + 0]/2
7.5 m/sec = v/2
v = (7.5 x 2) m/sec = 15 m/secSource(s): http://myrank.co.in/
- oubaasLv 77 months ago
Vav = d/t = 60/8 = 15/2 = 7.5 m/sec
peak speed Vpk = Vav*2 = 15.0 m/sec
- electron1Lv 77 months ago
To determine the average velocity, divide the distance by the time.
Average velocity = 60 ÷ 8 = 7.5 m/s
Let’s use the following equation to determine the object’s velocity at 8 seconds.
Average velocity = ½ * (vi + vf), vi = 0
½ * vi = 7.5
vi = 15 m/s
During the 8 seconds, its velocity increases from 0 m/s to 15 m/s. Let’s use the following equation to determine the acceleration.
vf = vi + a * t, vi = 0
15 = a * 8
a = 1.875 m/s^2
I hope this is helpful for you.
- billrussell42Lv 77 months ago
60 m / 8s = 7.5 m/s
Average speed is total distance divided by total time. And since this is straight line motion, average velocity is the same.