Could someone please help me with this physics problem? The question is attached as an image. Please help?
- electron1Lv 74 months ago
At point A, the projectile has its maximum positive vertical velocity. At point B, its vertical velocity is 0 m/s. At point C, it has its maximum negative vertical velocity. The vertical velocity is always decreasing, because the vertical acceleration is negative 9.8 m/s^2. The first answer is the correct answer. I hope this is helpful for you.
- oubaasLv 74 months ago
Vy = Voy-g*t
Vy decreases at constant rate g*t
- Jim MoorLv 74 months ago
v = a * t
so 'v' decreases at a constant rate
(becomes negative starting at the top)
- nyphdinmdLv 74 months ago
"velocity" is a vector. the vertical component of the velocity is given by v_y(t) = -gt + v_y0 where v_y0 is the start value of the vertical component. Since -gt gets small with increasing t, that is it gets more negative, v_y(t) decreases with time and at a constant rate - answer a