Anonymous asked in Science & MathematicsPhysics · 4 months ago

Could someone please help me with this physics problem? The question is attached as an image. Please help?

Attachment image

4 Answers

  • 4 months ago

    At point A, the projectile has its maximum positive vertical velocity. At point B, its vertical velocity is 0 m/s. At point C, it has its maximum negative vertical velocity. The vertical velocity is always decreasing, because the vertical acceleration is negative 9.8 m/s^2. The first answer is the correct answer. I hope this is helpful for you.

  • oubaas
    Lv 7
    4 months ago

    Vy = Voy-g*t

    Vy decreases at constant rate g*t

  • 4 months ago

    v = a * t

    so 'v' decreases at a constant rate

    (becomes negative starting at the top)

  • 4 months ago

    "velocity" is a vector. the vertical component of the velocity is given by v_y(t) = -gt + v_y0 where v_y0 is the start value of the vertical component. Since -gt gets small with increasing t, that is it gets more negative, v_y(t) decreases with time and at a constant rate - answer a

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