# What is the hypotenuse of a 1 inch square?

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• The answer is sqrt(2) = ~1.414...

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• Using Pythagoras its diagonal or hypotenuse is the square root of 2 inches

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• The diagonal of a square will be the hypotenuse of the two right angled triangles that make up the square.

Use Pythagoras; The square on the hypotenuse = sum of squares on the other two sides.

h^2 = 1^2 + 1^2

h^2 = 1 + 1

h^2 = 2

h = 1.41 inches

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• The diagonal of the square will measure 1.414 inches.

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• As Jeff said, squares do not have hypotenuses. the diagonal is √2 inches.

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• √ 2 is the hypotenuse length.

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• By Pythagoras

h^2 = 1^2 + 1^2

h^2 = 2

h = sqrt(2) (The hypotenuse).

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• I assume you are looking for the diagonal of the square.

You can use the Pythagorean Theorem:

a² + b² = c²

The sides (legs) are each 1 inch long. They hypotenuse (c) is unknown:

1² + 1² = c²

2 = c²

Take the square root of both sides:

c = √2 ≈ 1.414

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