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# 10 coulombs of positive charge flow from 9v positive terminal to negative terminal 3v. what is the change in potential energy of charge?

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- oubaasLv 77 months ago
ΔV = 9-3 = 6.0 V

ΔPE = ΔV*Q = 6.0 V * 10.0 A*sec = 60.0 V*A*sec (joule)

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- Andrew SmithLv 77 months ago
The change in volts is 9-3 = 6 V

but the definition of a volt is a JOULE per COULOMB

So the potential energy LOST is 6 V = 6 Joules per coulomb.

And the total potential energy lost is 6*10 = 60 Joules.

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