Anonymous
Anonymous asked in Science & MathematicsChemistry · 6 months ago

Chemistry question?

What is the concentration (molarity) of rubidium oxalate, Rb2C2O4 in a solution prepared by adding 66.38g of rubidium oxalate to enough water to make 250.0 mL of solution? Assume the solid fully dissolves.

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    66.38 g in 250 mL is 66.38 * 4 grams in 1 liter

    66.38 * 4 =>

    240 + 24 + 1.2 + 0.32 =>

    264 + 1.52 =>

    265.52

    Now, find the molar mass of Rb[2]C[2]O[4]

    Rubidium has a mass of 85.4678 grams/mol

    Carbon has a mass of 12 grams/mol

    Oxygen has a mass of 16 grams/mol

    2 * 85.4678 + 2 * 12 + 4 * 16 =>

    170.9356 + 24 + 64 =>

    170.9356 + 88 =>

    258.9356

    1 mole of rubidium oxalate will have a mass of 258.9356

    265.52 / 258.9356 =>

    1.0254287166384228356394408493849...

    Take it to 4sf

    1.025 M

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  • 6 months ago

    (66.38 g Rb2C2O4) / (258.9546 g Rb2C2O4/mol) / (0.2500 L) = 1.025 mol/L Rb2C2O4

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