What is the density (in g/cm^3) of a piece of copper that has a mass of 1.12 oz and occupies a volume of 3.54 mL?
I did d=m/v but still got the answer wrong
5 Answers
- pisgahchemistLv 75 months agoFavorite Answer
Density ....
Convert ounces to grams. Everyone knows that 1 milliliter is equivalent to 1 cubic centimeter.
D = m / V
D = (1.12 oz x 28.3495 g / 1 oz) / 3.54 cm³ = 8.97 g/cm³
The answer can only be expressed to three significant digits.
- Anonymous5 months ago
31.75147 grams/3.54 cm³ = 8.97 g/cm³
- A.J.Lv 75 months ago
Assumption 1: "Mass" 1.12 oz is Avp (Avoirdupois) weight and not troy of precious and semi-precious metals. (The teacher or book could have an error in this)
Assumption 2: The "volume" means displacement of water at standard conditions.
Without these assumptions, the numbers change.
1 AVP ounce = 28.3495231 grams
3.54 mL water = 3.54 cm³.
1.12 * 28.3495231 grams = 31.75147 grams
31.75147 grams/3.54 cm³ = 8.97 g/cm³
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- 5 months ago
Convert ounces to grams
1 pound = 453.59237 grams, exactly
1 ounce = 1/16 pounds = 453.59237/16 grams
1.12 ounces =>
1.12 * 453.59237 / 16 grams =>
0.07 * 16 * 453.59237 / 16 grams =>
0.07 * 453.59237 grams =>
7 * 4.5359237 grams =>
31.7514659 grams
1 ml occupies 1 cubic cm of space
31.7514659 / 3.54 grams/cm^3 =>
8.9693406497175141242937853107345... grams/cm^3
8.97 g/cm^3, taken to 3 sf
EDIT: Google confirms that we're at least on the right track