Anonymous
Anonymous asked in Science & MathematicsChemistry · 5 months ago

What is the density (in g/cm^3) of a piece of copper that has a mass of 1.12 oz and occupies a volume of 3.54 mL?

I did d=m/v but still got the answer wrong

5 Answers

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  • 5 months ago
    Favorite Answer

    Density ....

    Convert ounces to grams. Everyone knows that 1 milliliter is equivalent to 1 cubic centimeter.

    D = m / V

    D = (1.12 oz x 28.3495 g / 1 oz) / 3.54 cm³ = 8.97 g/cm³

    The answer can only be expressed to three significant digits.

  • Anonymous
    5 months ago

    31.75147 grams/3.54 cm³ = 8.97 g/cm³

  • 5 months ago

    Did you pay any attention to the units?

  • A.J.
    Lv 7
    5 months ago

    Assumption 1: "Mass" 1.12 oz is Avp (Avoirdupois) weight and not troy of precious and semi-precious metals. (The teacher or book could have an error in this)

    Assumption 2: The "volume" means displacement of water at standard conditions.

    Without these assumptions, the numbers change.

    1 AVP ounce = 28.3495231 grams

    3.54 mL water = 3.54 cm³.

    1.12 * 28.3495231 grams = 31.75147 grams

    31.75147 grams/3.54 cm³ = 8.97 g/cm³

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  • Convert ounces to grams

    1 pound = 453.59237 grams, exactly

    1 ounce = 1/16 pounds = 453.59237/16 grams

    1.12 ounces =>

    1.12 * 453.59237 / 16 grams =>

    0.07 * 16 * 453.59237 / 16 grams =>

    0.07 * 453.59237 grams =>

    7 * 4.5359237 grams =>

    31.7514659 grams

    1 ml occupies 1 cubic cm of space

    31.7514659 / 3.54 grams/cm^3 =>

    8.9693406497175141242937853107345... grams/cm^3

    8.97 g/cm^3, taken to 3 sf

    EDIT: Google confirms that we're at least on the right track

    https://www.google.com/search?q=copper+density

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